Answer to Question #346213 in Physics for Esau

Question #346213

A 65.0-kg runner has a speed of 5.20 m/s at one instant during a long-distance

event. (a) What is the runner’s kinetic energy at this instant? (b) How much net

work is required to double his speed?


1
Expert's answer
2022-05-30T15:17:27-0400

(a)

Ek1=mv122=65.05.2022=879JE_{k1}=\frac{mv_1^2}{2}=\frac{65.0*5.20^2}{2}=879\:\rm J

(b)

W=Ek2Ek1=4Ek1Ek1=3Ek1=3879=2640JW=E_{k2}-E_{k1}=4E_{k1}-E_{k1}=3E_{k1}\\ =3*879=2640\:\rm J


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