IV. An iron wire 1.0 m long with a square cross-section 2.0 mm on a side is used
to support a 100 kg load. Find the change in length.
"\\frac{F}{A}=\\frac{\\Delta l}{l_0}E"
"\\Delta l=\\frac{Fl_0}{AE}=\\frac{mgl_0}{AE}"
"\\Delta l=\\frac{100*9.8*1.0}{4.0*10^{-6}*200*10^9}\\\\\n=1.23*10^{-3}\\:\\rm m=1.23\\: mm"
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