An object is projected from the ground with an initial velocity of 20.25 m/s at 50degrees above the horizontal. Find the following. (Show your complete solution.) a. Horizontal and vertical components of its initial velocity b.. Time to reach the maximum height c. Range
Given:
"v_0=20.25\\:\\rm m\/s"
"\\theta=50^\\circ"
(a)
"v_{0x}=v_0\\cos\\theta=20.25*\\cos50^\\circ=13.0\\:\\rm m\/s""v_{0y}=v_0\\sin\\theta=20.25*\\sin50^\\circ=15.5\\:\\rm m\/s"
(b)
"t_1=\\frac{v_{0y}}{g}=\\frac{15.5}{9.8}=1.58\\rm\\: s"(c)
"R=v_{0x}*2t_1\\\\\n=13.0*2*1.58=41.2\\;\\rm m"
Comments
Leave a comment