Question

An arrow moving at 10 m/s is stopped by a target. If the arrow has a mass of 250 g and penetrates 4 cm into the target, what is the force exerted by the arrow on the target?

Answer 1

The energy-work theorem says

$$\frac{mv^2}{2}=Fd$$

$$F=\frac{mv^2}{2d}=\frac{0.250*10^2}{2*0.04}=313\:\rm N$$