Question

Determine the magnetic feild at the center of the semicircular piece of wire with radius 0.20 m. The current carried by the semi circular piece of wire is 150 A.

Answer 1

The magnetic field at the center of semicircular loop

$$B=\frac{\mu_0 I}{4 r}$$ $$B=\frac{4\pi*10^{-7}*150}{4*0.20}=2.4*10^{-4}\:\rm T$$