Answer to Question #309301 in Physics for Elijah

Question #309301

A car is speeding up and has an instantaneous velocity of 1.0 m/s in the +x-direction when a stopwatch reads 10.0 s. It has a constant acceleration of 2.0 m/s2 in the x-direction. (a) What change in speed occurs between t = 10.0 s and t = 12.0 s? (b) What is the speed when the stopwatch reads 12.0 s?


1
Expert's answer
2022-03-13T18:49:21-0400

a) The change in speed is given as follows, according to the kinematic equation:




Δv=aΔt\Delta v = a\Delta t

where a=2m/s2a= 2m/s^2 is the acceleration, and Δt=12s10s=2s\Delta t = 12s-10s = 2s is the time interval. Thus, obtain:




Δv=2m/s22s=4m/s\Delta v = 2m/s^2\cdot 2s = 4m/s

b) The speed at 12s is:




v=v0+Δvv = v_0 + \Delta v

where v0=1m/sv_0 = 1m/s is the initial speed. Thus, have:




v=1m/s+4m/s=5m/sv = 1m/s + 4m/s = 5m/s

Answer. a) 4m/s, b) 5m/s.


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