Answer to Question #309290 in Physics for Elijah

Question #309290

A car is speeding up and has an instantaneous velocity of 1.0 m/s in the +x-direction when a stopwatch reads 10.0 s. It has a constant acceleration of 2.0 m/s2 in the x-direction. (a) What change in speed occurs between t = 10.0 s and t = 12.0 s? (b) What is the speed when the stopwatch reads 12.0 s?

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Expert's answer
2022-03-10T18:00:58-0500

(a) the change in speed occurs between = 10.0 s and t = 12.0 s

Δv=aΔt=2.0m/s22.0s=4.0m/s\Delta v=a\Delta t\\ =\rm 2.0\: m/s^2*2.0\: s=4.0\: m/s

(b) the the speed when the stopwatch reads 12.0 s

v2=v1+Δv=1.0m/s+4.0m/s=5.0m/sv_2=v_1+\Delta v\\ =\rm 1.0\: m/s+4.0\: m/s=5.0\: m/s


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