Question

A gas with a constant pressure of 150 kPa expands from a volume of 0.76 m³ to a volume of 0.92 m³. How much work does the gas do?

Answer 1

The work is given as follows:

$$W = p\Delta V - p(V_2-V_1)$$

where $p = 150\times 10^3Pa$, $V_2 = 0.92m^3, V_1 = 0.76m^3$. Thus, obtain:

$$W = 150\times 10^3Pa\cdot (0.92m^3-0.76m^3) = 24\times 10^3J = 24kJ$$

Answer. 24kJ.