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Answer to Question #307777 in Physics for yourme

Question #307777

An electric field (E=4.5N/C) passes through a flat surface area (0.30m) with an angle of 45°. What will be the magnitude of the electric flux?


1
Expert's answer
2022-03-08T08:56:49-0500

The electric flux

"\\Phi=EA\\cos\\theta\\\\\n=\\rm 4.5\\:N\/C*0.3\\:m^2*\\cos45^\\circ=0.95\\:N\\cdot m^2\/C"


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