Answer to Question #307701 in Physics for Ejhay

Question

Sphere A, with a charge of +6.0 𝜇𝐶, is located near another charged sphere, B. Sphere B has a charge of −3.0 𝜇𝐶and is located 4.0 cm to the right of A.

What is the force of sphere B on sphere A?

A third sphere, C with a +1.5 𝜇𝐶charge, is added to the configuration. If it is located 3.0 cm directly beneath A, what is the new net force on sphere A?

Answer 1

The Coulomb's law says

$$F=k\frac{q_1q_2}{r^2}$$ $$F_1=9*10^9*\frac{6*10^{-6}*3*10^{-6}}{(0.04)^2}=101\:\rm N$$