Question

The plates of a parallel-plate capacitor are 2.50mm apart, and each carries a charge of magnitude 80.OnC. The plates are in vacuum. The electric field between the plates has a magnitude of 4.00 * 106V / m . What is the potential difference between the plates?

Answer 1

The potential difference between the plates

$$V=Ed\\ =\rm 4.00 * 10^6\:V / m* 2.50*10^{-3} \: m=1*10^4\: V$$