How much charge flows from each terminal of a 12.0-V battery when it is connected to a 5.00-μF capacitor?
The charge is given as the product of capacitance and voltage:
"Q= CV = 5\\times 10^{-6}F\\cdot 12V = 60.0\\times 10^{-6}C"
Answer. "60.0\\times 10^{-6}C".
Comments
Leave a comment