An object is 3cm in front of a convex lens with 2cm focal length.
Find: a) the image distance
B)the magnification.
C)the image description: real or virtual? erect or inverted?
Given:
"d_o=3\\:\\rm cm"
"f=-2\\:\\rm cm"
The thin lens equation says
"\\frac{1}{d_0}+\\frac{1}{d_i}=\\frac{1}{f}"Hence:
a) the image distance
"d_i=\\frac{fd_o}{d_o-f}=\\frac{-2*3}{3-(-2)}=-1.2\\:\\rm cm"b) the magnification
"m=-\\frac{d_i}{d_0}=0.4"c) virtual, direct.
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