Answer to Question #305954 in Physics for Kelly

Question

A constant force on 40n act on a body initially at rest give it an acceleration of 0.1mls for 4seconds.calculate the work done by the force

Answer 1

During this time the body will cover the following distance:

$$d = \dfrac{at^2}{2}$$

where $a$ is the acceleration, and $t$ is time.

By definition, the work is the product of the force and distance:

$$W = Fd = \dfrac{Fat^2}{2}= \dfrac{40\cdot0.1\cdot 4^2 }{2} = 32J$$

Answer. 32J.