Answer to Question #305954 in Physics for Kelly

Question #305954

A constant force on 40n act on a body initially at rest give it an acceleration of 0.1mls for 4seconds.calculate the work done by the force


1
Expert's answer
2022-03-04T13:23:04-0500

During this time the body will cover the following distance:


d=at22d = \dfrac{at^2}{2}

where aa is the acceleration, and tt is time.

By definition, the work is the product of the force and distance:


W=Fd=Fat22=400.1422=32JW = Fd = \dfrac{Fat^2}{2}= \dfrac{40\cdot0.1\cdot 4^2 }{2} = 32J

Answer. 32J.


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