A proton (+q) is 50nm away from an electron (-q) which is 30nm away from another proton (+2q) with
a charge +2q. What is the net electric force on +2q?
The net force
"F=F_{12}-F_{13}=k\\frac{q*2q}{r_{12}^2}-k\\frac{q*2q}{r_{13}^2}""F=9*10^9*2*(1.6*10^{-19})\\\\\n\\times\\left(\\frac{1}{(30*10^{-9})^2}-\\frac{1}{(80*10^{-9})^2}\\right)=4.4*10^{-13}\\:\\rm N"
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