Answer to Question #305895 in Physics for Mjrocky

Question #305895

A spring 20cm long is stretched to 25cm by a load of 50N. What will be it's length when stretched by 100N assuming that the elastic limit is not reached

Expert's answer

The Hooke's law says

"F=k\\Delta l"

Hence

"l_2=\\frac{F_2}{F_1}(l_1-l_0)+l_0\\\\\n=100\/50*(25-20)+20=30\\:\\rm cm"

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