Answer to Question #305823 in Physics for percy

Question #305823

What is the magnitude of the repulsive force of two protons in a nucleus if the charge on each proton is 1.6 X 10 ^-19 C and the protons are 3 X 10 ^-15 m apart?

Expert's answer

"F=k\\frac{q_1q_2}{r^2}""F=9*10^9*\\frac{1.6*10^{-19}*1.6*10^{-19}}{(3*10^{-15})^2}=25.6\\:\\rm N"

Learn more about our help with Assignments: Physics

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. Two point charges q1 = 25nC and q2 = -75nC are separated by a distance of 3.0 cm. Find the magnitude
2. What changes take place in the atomic structure of an element X with atomic number 88 and mass numbe
3. A 1550 kg car with it's engine off starts 100 meters high on hill A. It coasts down hill A then
4. A girl weighing 470N hangs suspended on the end of a rope 8 meters long. What will be her gain in po
5. A kicked football leaves the ground at an angle θ = 38.8° with a velocity of 22.1 m/s. a) Calculat
6. A motorist traveling with a constant speed of 20.0 m/s passes a school-crossing corner, where the sp
7. Two identically charged one-peso coins are 1.5 m apart on a table. What is the charge of the coins i