Answer to Question #305823 in Physics for percy

Question #305823

What is the magnitude of the repulsive force of two protons in a nucleus if the charge on each proton is 1.6 X 10 ^-19 C and the protons are 3 X 10 ^-15 m apart?

Expert's answer

"F=k\\frac{q_1q_2}{r^2}""F=9*10^9*\\frac{1.6*10^{-19}*1.6*10^{-19}}{(3*10^{-15})^2}=25.6\\:\\rm N"

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