Answer to Question #305017 in Physics for DIVINEPRUDISIMO

Question #305017

A 450 kg satellite was launched by a popular TV station to orbit Earth.




How far should it be from the Earth’s surface to experience 4.25 x 103 N




of gravitational force?

1
Expert's answer
2022-03-02T10:14:07-0500
F=GMm(R+h)2F=G\frac{Mm}{(R+h)^2}

h=GMmFR=6.6710115.9710244504.251036378103=1.15105mh=\sqrt{\frac{GMm}{F}}-R\\ =\sqrt{\frac{6.67*10^{-11}*5.97*10^{24}*450}{4.25*10^3}}-6378*10^3\\ =1.15*10^5\:\rm m


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