Question #305000

Your father bought a car battery that has a terminal voltage of 12.6V for 75.0A, and 14.1V for 60.0A. What is the electromotive force and internal resistance of this car battery that your father bought?


Expert's answer

The Ohm's law says

I1=ER1+rI_1=\frac{\cal E}{R_1+r}

I2=ER2+rI_2=\frac{\cal E}{R_2+r}

or

I1=EV1/I1+rI_1=\frac{\cal E}{V_1/I_1+r}

I2=EV2/I2+rI_2=\frac{\cal E}{V_2/I_2+r}

We get

75=E12.6/75+r75=\frac{\cal E}{12.6/75+r}

60=E14.1/60+r60=\frac{\cal E}{14.1/60+r}


Roots:

r=0.1Ω,  E=20.1Vr=0.1\Omega, \;\cal E=20.1\:\rm V


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