Answer to Question #304871 in Physics for Shane

Question #304871

A parallel plate capacitor having a plate area of 0.70 m2 and a plate separation of 1.0 mm is connected to a source with a


voltage of 50 V. Find the capacitance, the charge on the plates, and the energy of the capacitor when there is air


between the plates.

1
Expert's answer
2022-03-03T12:05:26-0500

The capacitance

C=ϵ0Ad=8.8510120.700.001=6.2109FC=\frac{\epsilon_0 A}{d}\\ =\frac{8.85*10^{-12}*0.70}{0.001}=6.2*10^{-9}\:\rm F

The charge on the plates

q=CV=6.210950=3.1107Cq=CV=6.2*10^{-9}*50=3.1*10^{-7}\:\rm C

The energy of the capacitor

W=CV22=6.21095022=7.8106JW=\frac{CV^2}{2}=\frac{6.2*10^{-9}*50^2}{2}=7.8*10^{-6}\:\rm J


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