“A train of mass 120,000 kg is moving with velocity of 10m/s and is acted upon by a forward force of 7000 N due to engine and frictional force of 750 N. What will be the velocity of the train after 1,000 seconds?”
The Newton's second law says
"a=\\frac{F_{net}}{m}=\\frac{7000-750}{120000}=0.052\\:\\rm m\/s^2"The final speed
"v_f=v_i+at\\\\\n=10+0.052*1000=62\\:\\rm m\/s"
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