Answer to Question #304212 in Physics for lea

Question #304212

A steel rod 4 m long and 0.5 cm2





in cross sectional area is found to stretch 0.2





cm under a tension of 12000 N. Under these conditions, determine




(a) The stress




(b) The strain; and




(c) Young’s modulus for the material

1
Expert's answer
2022-03-01T11:12:23-0500

Given:

l0=4ml_0=4\:\rm m

A=0.5104m2A=0.5*10^{-4}\:\rm m^2

Δl=0.002m\Delta l=0.002\:\rm m

F=12000NF=12000\:\rm N

(a) The stress

σ=FA=120000.5104=2.4108Pa\sigma=\frac{F}{A}=\frac{12000}{0.5*10^{-4}}=2.4*10^8\:\rm Pa

(b) The strain

ε=Δll0=0.0024=5104\varepsilon=\frac{\Delta l}{l_0}=\frac{0.002}{4}=5*10^{-4}

(c) The Young’s modulus for the material

E=σε=2.41085104=4.81011PaE=\frac{\sigma}{\varepsilon}=\frac{2.4*10^8}{5*10^{-4}}=4.8*10^{11}\:\rm Pa


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