Question

5. Compute the electrostatic force experienced by -4.33 x 10-18 C from the following electricfield.

(a) E = 5 465 N/C

(b) 9.5 x 1015 N/C

Answer 1

The electrostatic force

$$F=qE$$

(a)

$$F=4.33*10^{-18}*5465=2.37*10^{-14}\:\rm N$$

(b)

$$F=4.33*10^{-18}*9.5*10^{15}=0.041\:\rm N$$