Answer to Question #302854 in Physics for Lance

Question

Find the instantaneous velocity at time 𝑡1=1.0 𝑠 using the equation 𝑥=20 𝑚+(5.0𝑚/𝑠^2)𝑡^2 during the time interval between t1=1.0 s and t2=2.0 s

Answer 1

Given:

$𝑥=20 𝑚+(5.0𝑚/𝑠^2)𝑡^2$

The instantaneous velocity

$$v=x'=({10.0\:\rm m/s})t$$

At the instant $t_1=1.0\:\rm s$

$$v(1.0)=({10.0\:\rm m/s})*1.0=10.0\:\rm m/s$$