Question

an object moving in simple harmonic motion has an amplitude of 0.02m and a frequency of 20hz. find the acceleration and velocity

Answer 1

The equation of SHM

$$x=A\cos(2\pi ft)=0.02\cos(40\pi t)$$

The velocity

$$v=x'=-0.8\pi\sin(40\pi t)$$

The acceleration

$$a=v'=-32\pi^2\cos(40\pi t)$$