Answer to Question #301265 in Physics for Lei

Question #301265

Evaluate:




HORIZONTAL MOTION




1. The motion of a particle along the x -axis is described by the equation




m v = (3 s2) t + (0.5 m) t2 s2




where x is in meters, and t is in seconds. Determine the following:




a. Position of the particle 3 seconds after starting




b. Displacement from 2 sec to 5 sec c. Average velocity during first 5 seconds d. Velocity at t = 4secs




UARM:




e. Average acceleration during the second 3 seconds




f. Acceleration at t = 5 secs g. Time the particle moves at 20m/s




h. The acceleration and velocity at start of motion 1. A car is moving at uniform acceleration. Its velocity

1
Expert's answer
2022-02-23T08:31:56-0500

x(t)=3t+0.5t2x(t)= 3t +0.5t^2


a. Position of the particle 3 seconds after starting

x(3)=33+0.532=13.5mx(3)= 3*3 +0.5*3^2=13.5\:\rm m

b. Displacement from 2 sec to 5 sec

x(5)x(2)=(35+0.552)(25+0.522)=15.5mx(5)-x(2)=(3*5+0.5*5^2)\\ -(2*5+0.5*2^2)=15.5\:\rm m

c. Average velocity during first 5 seconds

x(5)=35+0.552=27.5mx(5)= 3*5 +0.5*5^2=27.5\:\rm m

vave=x(5)t=27.55=5.5m/sv_{\rm ave}=\frac{x(5)}{t}=\frac{27.5}{5}=5.5\:\rm m/s

d. Velocity at t = 4sec

v=x=3+tv=x'=3+t

v(4)=3+4=12m/sv(4)=3+4=12\:\rm m/s


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