A car is moving at uniform acceleration. Its velocity after traveling for 2 seconds is 4m/s
and is found 12 meters from where it started. If the car’s velocity at 5 seconds is 10 m/s,
determine (a) the car’s acceleration, (b) its displacement at t = 5 seconds measured
from its starting point and (c) its velocity at the start.
The distance traveled by a car
"d=\\frac{v_i+v_f}{2}t"The initial speed
"v_i=2d\/t-v_f=2*12\/2-4=8\\:\\rm m\/s"The acceleration
"a=\\frac{v_f-v_i}{t}=\\frac{4-8}{2}=-2\\:\\rm m\/s^2"The displacement for the 5 sec
"d=v_it+at^2\/2=8*5+(-2)*5^2\/2=15\\:\\rm m"
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