A 1200kg car going 30m/s applies its brakes and skids to rest. If the friction force between sliding tiresband pavement is 600N. How far does the car skids before coming tonrest.
Given:
"v_0=30\\:\\rm m\/s"
"m=1200\\:\\rm kg"
"F=600\\:\\rm N"
The energy-work theorem says
"0-\\frac{mv_0^2}{2}=W=-Fd"The distance traveled before car coming to the rest
"d=\\frac{mv_0^2}{2F}=\\frac{1200*30^2}{2*600}=900\\:\\rm m"
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