A 100 kg block is pulled at a constant speed of 5 m/s across a horizontal force by an applied force of 122 N directed 37 o above the horizontal. The rate at which the force does work on the block is.
Given:
"m=100\\:\\rm kg"
"v=5\\:\\rm m\/s"
"\\theta=37^\\circ"
"F=122\\:\\rm N"
The rate of work done (power) is given by
"P=\\frac{W}{t}=\\frac{Fd\\cos\\theta}{t}=Fv\\cos\\theta""P=122*5*\\cos37^\\circ=487\\:\\rm W"
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