Question #299892

two particles a and b are released from rest, having equal charges of -8 x10-6 c and initially separated from each other by 0.025m. the masses of particles a and b are 6.25 x10-6 kg and 3.75x10-6 kg respectively. find the magnitude of the initial accelerations of particles a and b.


Expert's answer

Given:

q1=q2=−8∗10−6 Cq_1=q_2=\rm -8 *10^{-6}\: C

m1=6.25∗10−6 kgm_1=\rm 6.25*10^{-6}\: kg

m2=3.75∗10−6 kgm_2=\rm 3.75*10^{-6}\: kg

r=0.025 mr=0.025\:\rm m


The Coulomb's law says



F=k∣q1∣∣q2∣r2F=k\frac{|q_1||q_2|}{r^2}F=9∗109(8.0∗10−6)20.0252=921.6 NF=9*10^9\frac{(8.0*10^{-6})^2}{0.025^2}=921.6 \:\rm N


The acceleration of particles


a1=Fm1=921.66.25∗10−6=1.47∗108 m/s2a_1=\frac{F}{m_1}=\frac{921.6}{6.25*10^{-6}}=1.47*10^8\:\rm m/s^2a2=Fm2=921.63.75∗10−6=2.46∗108 m/s2a_2=\frac{F}{m_2}=\frac{921.6}{3.75*10^{-6}}=2.46*10^8\:\rm m/s^2
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