Answer to Question #299222 in Physics for ezekiel

Question #299222

a 10kg mass is suspended from the end of a spring and released. If the spring oscillates in shm with a period of 0.5s Cal the energy given to the 10kg Mass if the amplitude of oxidation is 2cm?


1
Expert's answer
2022-02-20T15:45:54-0500

Given:

m=10kgm=10\:\rm kg

T=0.5sT=0.5\:\rm s

A=0.02mA=0.02\:\rm m


The energy of a SHM

E=mω2A22=4mπ2A22T2E=\frac{m\omega^2A^2}{2}=\frac{4m\pi^2A^2}{2T^2}

E=410π20.02220.52=0.32JE=\frac{4*10*\pi^2*0.02^2}{2*0.5^2}=0.32\:\rm J


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Comments

Ezekiel
21.02.22, 21:26

Very good, Thanks.

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