A ball of mass m = 0.490 kg is dropped near the surface of the Earth. However, there exists an air resistance F = −βv, where β = 0.700 N · s/m. After a long time, the ball approaches a speed v. What is this speed?
Given:
"m=0.490\\:\\rm kg"
"\\beta=0.700\\:\\rm N\\cdot s\/m"
"g=9.8\\:\\rm m\/s^2"
The terminal velocity of a ball
"v_t=\\frac{mg}{\\beta}=\\frac{0.490*9.8}{0.700}=6.86\\:\\rm m\/s"
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