Answer to Question #299134 in Physics for Grasyaxxx

Question

Find the electrostatic force between charges of +2.0C and +5.0 separated by a distance of 75m in a vacuum

Answer 1

Given:

$q_1=2.0\:\rm C$

$q_2=5.0\:\rm C$

$r=75\:\rm m$

The Coulomb's law says

$$F=k\frac{|q_1||q_2|}{r^2}$$ $$F=9*10^9\frac{2.0*5.0}{75^2}=1.6*10^7 \:\rm N$$

The force is repulsive.