A proton is placed in uniform electric field that is directed downward and has a magnitude of 5.0 N/C. What is the magnitude and direction of the electric force experience by the proton?
Given:
E=5.0 N/CE=5.0\:\rm N/CE=5.0N/C
e=1.6∗10−19 Ce=1.6*10^{-19}\:\rm Ce=1.6∗10−19C
The electric force on a charge
The force is directed downward.
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