the energy used by an electric iron for 1 minute is 33 kJ, at a voltage of 220 volts. How large the current is in the electric iron?
Given:
"t=60\\:\\rm s"
"W=33000\\:\\rm J"
"V=220\\;\\rm V"
The work done by electric field
"W=IVt"Thus, the electric current
"I=\\frac{W}{Vt}=\\frac{33000}{220*60}=2.5\\: \\rm A"
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