Question

What is the total electric flux through a closed surface containing a 2.0 μC charge?

Answer 1

Given:

$q=2.0*10^{-6}\:\rm C$

$\epsilon_0=8.85*10^{-12}\:\rm F/m$

The Gauss's law says

$$\phi=\oint {\bf E}d{\bf A}=\frac{q}{\epsilon_0}$$

Hence

$$\phi=\frac{2.0*10^{-6}\:\rm C}{8.85*10^{-12}\:\rm F/m}=2.3*10^5\: \rm V\cdot m$$