Question #298181

You built a circuit consisting of three parallel plate capacitors with capacitances of 2.0 F, 3.0 F, and 5.0 F, respectively, which are connected in parallel. The whole circuit is connected to a 100 V line. What is the (a) total capacitance, (b) charge stored in each capacitor, and (c) potential difference across each capacitor?



1
Expert's answer
2022-02-15T13:35:03-0500

Given:

C1=2.0FC_1=2.0\:\rm F

C2=3.0FC_2=3.0\:\rm F

C3=5.0FC_3=5.0\:\rm F

V=100VV=100\:\rm V


(a)  the total capacitance

C=C1+C2+C3=2.0+3.0+5.0=10FC=C_1+C_2+C_3=\rm 2.0+3.0+5.0=10\rm \: F

(b) charge stored in each capacitor

q1=C1V=2.0100=200Cq2=C2V=3.0100=300Cq3=C3V=5.0100=500C{q_1=C_1V=\rm 2.0*100=200\:\rm C} \\ {q_2=C_2V=\rm 3.0*100=300\:\rm C} \\{q_3=C_3V=\rm 5.0*100=500\:\rm C}

(c) potential difference across each capacitor

V1=V2=V3=V=100VV_1=V_2=V_3=V=\rm 100\: V


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