Question #297580

A RACE CAR HAS A MASS OF 710 KG. IT STARTS FROM REST AND TRAVELS 40 M IN 3 S. THE CAR IS UNIFORMLY ACCELERATED DURING THE ENTIRE TIME. WHAT NET FORCE IS APPLIED TO IT ?


1
Expert's answer
2022-02-17T04:34:07-0500

Given:

m=710kgm=710\:\rm kg

v0=0v_0=0

d=40md=40\:\rm m

t=3st=3\:\rm s


The distance traveled by a car

d=v0t+at2/2=at2/2d=v_0t+at^2/2=at^2/2

Hence, the acceleration of the car

a=2dt2=24032=8.89m/s2a=\frac{2d}{t^2}=\frac{2*40}{3^2}=8.89\:\rm m/s^2

The Newton's second law says

F=ma=7108.89=6311NF=ma=710*8.89=6311\:\rm N


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