Answer to Question #297579 in Physics for Crieza

Question #297579

A 10 KG BLOCK LIES ON A FRICTIONLESS HORIZONTAL SURFACE.

A. WHAT FORCE WILL GIVE IT AN ACCELERATION OF 500 CM/S2 ?

B. WHAT CONSTANT FORCE WILL GIVE THE SAME BODY A VELOCITY OF 2 M/S AFTER 1 S ?


1
Expert's answer
2022-02-16T13:17:10-0500

Given:

m=10kgm=10\:\rm kg

a=500cm/s2=5m/s2a=500\:\rm cm/s^2=5\: m/s^2

Δv=2m/s\Delta v=2\:\rm m/s

Δt=1s\Delta t=1\: \rm s


(a) the Newton's second law says

F=ma=105=50NF=ma=10*5=50\:\rm N

(b)

F=ma=mΔvΔt=1021=20NF=ma=m\frac{\Delta v}{\Delta t}=10*\frac{2}{1}=20\:\rm N


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