Question #296700

A 2.5 KG MASS AND A 4 KG MASS ARE ATTACHED TO A LIGHT


WEIGHT CORD THAT PASSES OVER A FRICTIONLESS PULLEY. THE


HANGING MASSES ARE LEFT FREE TO MOVE. FIND THE


1
Expert's answer
2022-02-15T13:35:14-0500

Given:

m1=2.5kgm_1=\rm 2.5\: kg

m2=4kgm_2=\rm 4\: kg


The acceleration of system

a=gm2m1m2+m1=9.84.02.54.0+2.5=2.3m/s2a=g\frac{m_2-m_1}{m_2+m_1}=9.8*\frac{4.0-2.5}{4.0+2.5}=2.3\:\rm m/s^2


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