Question #296673

A particle moves in a straight line such that its displacement, x meters, from a fixed point O on the line at time t seconds is given by 𝑥 = 40[𝑒 −2𝑡 − 𝑒 −4𝑡 ].


(a) Find the time when the particle is instantaneously at rest.


(b) Find the displacement of the particle from O when t = 3 s.


(c) Find the total distance travelled during the first 3 seconds of its motion


1
Expert's answer
2022-02-13T12:14:33-0500

Given:

𝑥(t)=40[𝑒2𝑡𝑒4𝑡]𝑥 (t)= 40[𝑒^{−2𝑡} − 𝑒^{−4𝑡}]


(a) Find the time when the particle is instantaneously at rest:

x(t)=40[2𝑒2𝑡+4𝑒4𝑡]=0x'(t)=40[-2𝑒^{−2𝑡}+4 𝑒^{−4𝑡}]=0

𝑒2𝑡(2+4𝑒2𝑡)=0𝑒^{−2𝑡}(-2+4 𝑒^{−2𝑡})=0

𝑒2𝑡=1/2𝑒^{−2𝑡}=1/2

t=12ln2st=\frac{1}{2}\ln 2\:\rm s

(b) Find the displacement of the particle from O when t = 3 s:

d=x(3)=40[𝑒6𝑒12]=0.1md=x(3)=40[𝑒^{−6} − 𝑒^{−12}]=0.1\:\rm m

(c) Find the total distance travelled during the first 3 seconds of its motion

l=x(3)x(0)=0.10=0.1ml=x(3)-x(0)=0.1-0=0.1\:\rm m


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