Question

The pressure below the depth of 25 m of a homogenous fluid is 50.473 psi.

Calculate specific weight in kN/m3,density of fluid in kgm/m3 and its specific

gravity

Answer 1

Given:

$h=25\:\rm m$

$p=50.473\: \rm psi=347999\: Pa$

The specific weight

$$g\rho=\frac{P}{h}\\ =\frac{347999}{25}=13920\:\rm N/m^3=13.92\: kN/m^3$$

The density of fluid

$$\rho=\frac{P}{gh}=\frac{13920}{9.8}=1420\:\rm kg/m^3$$

The specific gravity

$$\rho/\rho_w=1420/1000=1.42$$