Answer to Question #296475 in Physics for deja

Question

A crane used 112.95 watts of power to raise a 17.74 N object in 4.05 seconds. Through what vertical distance was the object displaced?

Answer 1

Given:

$P=112.95\;\rm W$

$F=17.74\;\rm N$

$t=4.05\:\rm s$

The work done by the crane

$$W=Fh=Pt$$

Hence, the vertical distance the object was displaced

$$h=\frac{Pt}{F}=\rm\frac{112.95\: W*4.05\: s}{17.74\: N}=25.8\:\rm m$$