Answer to Question #296310 in Physics for Kazi

Question

A car accelerates from 10.0 m/s to 30.0 m/s at a rate of 3.00 m/s2. How far does the car travel while accelerating?

a. 226 m

b. 133 m

c. 399 m

d. 80 m

Answer 1

Given:

$v_1=10.0\:\rm m/s$

$v_2=30.0\:\rm m/s$

$a=3.00\:\rm m/s^2$

The distance traveled by a car

$$d=\frac{v_2^2-v_1^2}{2a}=\rm \frac{30.0^2-10.0^2}{2*3.00}=133\:\rm m$$

Answer: b. 133 m