Answer to Question #296310 in Physics for Kazi

Question #296310

A car accelerates from 10.0 m/s to 30.0 m/s at a rate of 3.00 m/s2. How far does the car travel while accelerating?


a. 226 m

b. 133 m

c. 399 m

d. 80 m


1
Expert's answer
2022-02-15T16:14:53-0500

Given:

v1=10.0m/sv_1=10.0\:\rm m/s

v2=30.0m/sv_2=30.0\:\rm m/s

a=3.00m/s2a=3.00\:\rm m/s^2


The distance traveled by a car

d=v22v122a=30.0210.0223.00=133md=\frac{v_2^2-v_1^2}{2a}=\rm \frac{30.0^2-10.0^2}{2*3.00}=133\:\rm m

Answer: b. 133 m


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