A lead pellet is propelled vertically upward by an air rifle with an initial speed of 50 ft/s. Find its maximum height ?
Given:
"v_0=50\\:\\rm ft\/s"
"g=32.17\\:\\rm ft\/s^2"
The maximum height
"h_{\\max}=\\frac{v_0^2}{2g}=\\frac{50^2}{2*32.17}=39\\:\\rm ft"
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