Question

Can you help me solve this question #Assignment# A spring of Force constant 1500Nm-¹ is acted upon by a constant force of 45N . calculate the potential energy stored in spring

Answer 1

Given:

$k=\rm 1500\:\rm N/m$

$F=45\:\rm N$

The deformation of spring

$$x=\frac{F}{k}=\frac{45\:\rm N}{1500\:\rm N/m}=0.03\:\rm m$$

The potential energy stored in spring

$$E_p=\frac{kx^2}{2}=\frac{1500*0.03^2}{2}=0.675\:\rm J$$