Question #295479

An object with a mass of 3.50 kg moves in a straight line on a frictionless horizontal surface with a speed of 2.0 m/s. Find the kinetic energy and the net work done on the object to make it reach this speed if it started from rest.


1
Expert's answer
2022-02-10T08:37:03-0500

Given:

vf=2.0m/sv_f=2.0\rm\: m/s

vi=0m/sv_i=0\rm\: m/s

m=3.50kgm=3.50\rm\: kg


The final kinetic energy

Ekf=mvf22=3.502.022=7.0JE_{kf}=\frac{mv_f^2}{2}=\frac{3.50*2.0^2}{2}=7.0\:\rm J

The work done

W=EkfEki=7.00=7.0JW=E_{kf}-E_{ki}=7.0-0=7.0\:\rm J


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