Answer to Question #294929 in Physics for hhaha

Question

How much work is done on the block if a 10.0 kg block was accelerated at 5.0 m/s2 with a distance of 2.5 m across a frictionless table?

Answer 1

Given:

$m=10.0\:\rm kg$

$a=5.0\:\rm m/s^2$

$d=2.5\:\rm m$

The force acting on a block

$$F=ma=\rm 10.0\: kg*5.0\: m/s^2=50.0\: N$$

The work done

$$W=Fd=\rm 50.0\: N*2.5\: m=125\: J$$