Question

The potential difference between two parallel plates of a condenser which are 4 mm apart is 800 V. (a) What is the potential gradient? (b) What is the force on a proton which is midway between the plates?

With complete Solution Thank you

Answer 1

Given:

$d=\rm 4 \: mm=0.004\: m$

$V=800\:\rm V$

(a) the potential gradient

$$E=\frac{V}{d}=\rm \frac{800\: V}{0.004\: m}=2*10^5\: V/m$$

(b) the force on a proton which is midway between the plates

$$F=qE\\ =\rm 1.6*10^{-19}\: C*2*10^5\: V/m=3.2*10^{-14}\: N$$