Answer to Question #294479 in Physics for Exes

Question

It took a man 3 seconds nto raise a load of 40kg to a hight of 25 m.Determine the average power employed.

Answer 1

Given:

$t=3\:\rm s$

$m=40\:\rm kg$

$h=25\:\rm m$

$g=9.8\:\rm N/kg$

The average power

$$P=\frac{W}{t}=\frac{mgh}{t}$$

$$P=\frac{40*9.8*25}{3}=3267\:\rm W$$